Base | Representation |
---|---|
bin | 110001011110111011111… |
… | …001010000110110001101 |
3 | 110001002012201000101210122 |
4 | 301132323321100312031 |
5 | 421203131144403431 |
6 | 11122053253114325 |
7 | 500450565454325 |
oct | 61367371206615 |
9 | 13032181011718 |
10 | 3400471481741 |
11 | 10a114a557304 |
12 | 46b04b0289a5 |
13 | 1b8880a49909 |
14 | ba82594a285 |
15 | 5d6c2720a7b |
hex | 317bbe50d8d |
3400471481741 has 2 divisors, whose sum is σ = 3400471481742. Its totient is φ = 3400471481740.
The previous prime is 3400471481711. The next prime is 3400471481779. The reversal of 3400471481741 is 1471841740043.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2188609566025 + 1211861915716 = 1479395^2 + 1100846^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3400471481741 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3400471481692 and 3400471481701.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3400471481711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700235740870 + 1700235740871.
It is an arithmetic number, because the mean of its divisors is an integer number (1700235740871).
Almost surely, 23400471481741 is an apocalyptic number.
It is an amenable number.
3400471481741 is a deficient number, since it is larger than the sum of its proper divisors (1).
3400471481741 is an equidigital number, since it uses as much as digits as its factorization.
3400471481741 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 301056, while the sum is 44.
The spelling of 3400471481741 in words is "three trillion, four hundred billion, four hundred seventy-one million, four hundred eighty-one thousand, seven hundred forty-one".
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