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34010041141 is a prime number
BaseRepresentation
bin11111101011001010…
…000000101100110101
310020210012220002200101
4133223022000230311
51024123032304031
623342441114101
72312541402616
oct375312005465
9106705802611
1034010041141
111347286631a
126711a88931
1332900c0ccb
141908c53c0d
15d40bd4361
hex7eb280b35

34010041141 has 2 divisors, whose sum is σ = 34010041142. Its totient is φ = 34010041140.

The previous prime is 34010041133. The next prime is 34010041217. The reversal of 34010041141 is 14114001043.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17227875025 + 16782166116 = 131255^2 + 129546^2 .

It is an emirp because it is prime and its reverse (14114001043) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34010041141 - 23 = 34010041133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34010041111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17005020570 + 17005020571.

It is an arithmetic number, because the mean of its divisors is an integer number (17005020571).

Almost surely, 234010041141 is an apocalyptic number.

It is an amenable number.

34010041141 is a deficient number, since it is larger than the sum of its proper divisors (1).

34010041141 is an equidigital number, since it uses as much as digits as its factorization.

34010041141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 34010041141 its reverse (14114001043), we get a palindrome (48124042184).

The spelling of 34010041141 in words is "thirty-four billion, ten million, forty-one thousand, one hundred forty-one".