Base | Representation |
---|---|
bin | 11111101011011011… |
… | …001011001010010001 |
3 | 10020210112100200112211 |
4 | 133223123023022101 |
5 | 1024130210243213 |
6 | 23343121352121 |
7 | 2312624552236 |
oct | 375333131221 |
9 | 106715320484 |
10 | 34014540433 |
11 | 13475359745 |
12 | 6713498641 |
13 | 3291007c03 |
14 | 19096a578d |
15 | d412c253d |
hex | 7eb6cb291 |
34014540433 has 2 divisors, whose sum is σ = 34014540434. Its totient is φ = 34014540432.
The previous prime is 34014540431. The next prime is 34014540509. The reversal of 34014540433 is 33404541043.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 28125973264 + 5888567169 = 167708^2 + 76737^2 .
It is an emirp because it is prime and its reverse (33404541043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34014540433 - 21 = 34014540431 is a prime.
Together with 34014540431, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 34014540395 and 34014540404.
It is not a weakly prime, because it can be changed into another prime (34014540431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17007270216 + 17007270217.
It is an arithmetic number, because the mean of its divisors is an integer number (17007270217).
Almost surely, 234014540433 is an apocalyptic number.
It is an amenable number.
34014540433 is a deficient number, since it is larger than the sum of its proper divisors (1).
34014540433 is an equidigital number, since it uses as much as digits as its factorization.
34014540433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 31.
The spelling of 34014540433 in words is "thirty-four billion, fourteen million, five hundred forty thousand, four hundred thirty-three".
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