Search a number
-
+
340151325511 is a prime number
BaseRepresentation
bin1001111001100101001…
…10010101001101000111
31012111222201201200211011
410330302212111031013
521033112214404021
6420132515223051
733401160363364
oct4746246251507
91174881650734
10340151325511
11121291612448
1255b0bba7a87
13260cb35549a
141266b86146b
158cac5d7de1
hex4f32995347

340151325511 has 2 divisors, whose sum is σ = 340151325512. Its totient is φ = 340151325510.

The previous prime is 340151325491. The next prime is 340151325529. The reversal of 340151325511 is 115523151043.

It is a strong prime.

It is an emirp because it is prime and its reverse (115523151043) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 340151325511 - 227 = 340017107783 is a prime.

It is a super-2 number, since 2×3401513255112 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (340151325571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170075662755 + 170075662756.

It is an arithmetic number, because the mean of its divisors is an integer number (170075662756).

Almost surely, 2340151325511 is an apocalyptic number.

340151325511 is a deficient number, since it is larger than the sum of its proper divisors (1).

340151325511 is an equidigital number, since it uses as much as digits as its factorization.

340151325511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 340151325511 its reverse (115523151043), we get a palindrome (455674476554).

The spelling of 340151325511 in words is "three hundred forty billion, one hundred fifty-one million, three hundred twenty-five thousand, five hundred eleven".