Base | Representation |
---|---|
bin | 1111011110000111011000… |
… | …10011001111010110111111 |
3 | 11110110021211122100012011111 |
4 | 13233003230103033112333 |
5 | 13424341133443412233 |
6 | 200204342022502451 |
7 | 10110604633043353 |
oct | 757035423172677 |
9 | 143407748305144 |
10 | 34020105450943 |
11 | a926933696587 |
12 | 39953a8594a27 |
13 | 15ca10b714201 |
14 | 8588209c1463 |
15 | 3dee1adceacd |
hex | 1ef0ec4cf5bf |
34020105450943 has 2 divisors, whose sum is σ = 34020105450944. Its totient is φ = 34020105450942.
The previous prime is 34020105450923. The next prime is 34020105450977. The reversal of 34020105450943 is 34905450102043.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 34020105450943 - 29 = 34020105450431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34020105450896 and 34020105450905.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34020105450923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17010052725471 + 17010052725472.
It is an arithmetic number, because the mean of its divisors is an integer number (17010052725472).
Almost surely, 234020105450943 is an apocalyptic number.
34020105450943 is a deficient number, since it is larger than the sum of its proper divisors (1).
34020105450943 is an equidigital number, since it uses as much as digits as its factorization.
34020105450943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 259200, while the sum is 40.
Adding to 34020105450943 its reverse (34905450102043), we get a palindrome (68925555552986).
The spelling of 34020105450943 in words is "thirty-four trillion, twenty billion, one hundred five million, four hundred fifty thousand, nine hundred forty-three".
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