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34021332111313 is a prime number
BaseRepresentation
bin1111011110001001101010…
…11010100100111111010001
311110110102000010111222212001
413233010311122210333101
513424401142010030223
6200205103442234001
710110650216350561
oct757046532447721
9143412003458761
1034021332111313
11a927403051688
12399568b355901
1315ca2758b1551
148588d9890da1
153dee8d9349ad
hex1ef1356a4fd1

34021332111313 has 2 divisors, whose sum is σ = 34021332111314. Its totient is φ = 34021332111312.

The previous prime is 34021332111311. The next prime is 34021332111317. The reversal of 34021332111313 is 31311123312043.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30058716351889 + 3962615759424 = 5482583^2 + 1990632^2 .

It is an emirp because it is prime and its reverse (31311123312043) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34021332111313 - 21 = 34021332111311 is a prime.

Together with 34021332111311, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (34021332111311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17010666055656 + 17010666055657.

It is an arithmetic number, because the mean of its divisors is an integer number (17010666055657).

Almost surely, 234021332111313 is an apocalyptic number.

It is an amenable number.

34021332111313 is a deficient number, since it is larger than the sum of its proper divisors (1).

34021332111313 is an equidigital number, since it uses as much as digits as its factorization.

34021332111313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 34021332111313 its reverse (31311123312043), we get a palindrome (65332455423356).

The spelling of 34021332111313 in words is "thirty-four trillion, twenty-one billion, three hundred thirty-two million, one hundred eleven thousand, three hundred thirteen".