Base | Representation |
---|---|
bin | 100110101011011101001100… |
… | …1111001101100000010111011 |
3 | 1122121122002220222212111001102 |
4 | 1031112322121321230002323 |
5 | 324043213000041001021 |
6 | 3203332445332242015 |
7 | 131443244615304251 |
oct | 11526723171540273 |
9 | 1577562828774042 |
10 | 340224121422011 |
11 | 9945126aa11102 |
12 | 321a9869a7030b |
13 | 117abcc64bc008 |
14 | 6002d147d85d1 |
15 | 29500244c800b |
hex | 1356e99e6c0bb |
340224121422011 has 2 divisors, whose sum is σ = 340224121422012. Its totient is φ = 340224121422010.
The previous prime is 340224121421981. The next prime is 340224121422019. The reversal of 340224121422011 is 110224121422043.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 340224121422011 - 226 = 340224054313147 is a prime.
It is not a weakly prime, because it can be changed into another prime (340224121422019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170112060711005 + 170112060711006.
It is an arithmetic number, because the mean of its divisors is an integer number (170112060711006).
Almost surely, 2340224121422011 is an apocalyptic number.
340224121422011 is a deficient number, since it is larger than the sum of its proper divisors (1).
340224121422011 is an equidigital number, since it uses as much as digits as its factorization.
340224121422011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 340224121422011 its reverse (110224121422043), we get a palindrome (450448242844054).
The spelling of 340224121422011 in words is "three hundred forty trillion, two hundred twenty-four billion, one hundred twenty-one million, four hundred twenty-two thousand, eleven".
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