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340224121422019 is a prime number
BaseRepresentation
bin100110101011011101001100…
…1111001101100000011000011
31122121122002220222212111001201
41031112322121321230003003
5324043213000041001034
63203332445332242031
7131443244615304262
oct11526723171540303
91577562828774051
10340224121422019
119945126aa1110a
12321a9869a70317
13117abcc64bc013
146002d147d85d9
1529500244c8014
hex1356e99e6c0c3

340224121422019 has 2 divisors, whose sum is σ = 340224121422020. Its totient is φ = 340224121422018.

The previous prime is 340224121422011. The next prime is 340224121422067. The reversal of 340224121422019 is 910224121422043.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 340224121422019 - 23 = 340224121422011 is a prime.

It is a super-2 number, since 2×3402241214220192 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (340224121422011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170112060711009 + 170112060711010.

It is an arithmetic number, because the mean of its divisors is an integer number (170112060711010).

Almost surely, 2340224121422019 is an apocalyptic number.

340224121422019 is a deficient number, since it is larger than the sum of its proper divisors (1).

340224121422019 is an equidigital number, since it uses as much as digits as its factorization.

340224121422019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 55296, while the sum is 37.

The spelling of 340224121422019 in words is "three hundred forty trillion, two hundred twenty-four billion, one hundred twenty-one million, four hundred twenty-two thousand, nineteen".