Base | Representation |
---|---|
bin | 100110101100000110001101… |
… | …1110011100110111010010000 |
3 | 1122121221112021100122121122120 |
4 | 1031120030123303212322100 |
5 | 324101133341223241422 |
6 | 3203441133322334240 |
7 | 131452513365542622 |
oct | 11530143363467220 |
9 | 1577845240577576 |
10 | 340312200212112 |
11 | 9948565910a817 |
12 | 3220294b35a380 |
13 | 117b73c22926ab |
14 | 60072ac4aac12 |
15 | 295247bd5745c |
hex | 135831bce6e90 |
340312200212112 has 40 divisors (see below), whose sum is σ = 897844953757056. Its totient is φ = 111023838366336.
The previous prime is 340312200212099. The next prime is 340312200212119. The reversal of 340312200212112 is 211212002213043.
It is a super-2 number, since 2×3403122002121122 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is not an unprimeable number, because it can be changed into a prime (340312200212119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75423800983 + ... + 75423805494.
Almost surely, 2340312200212112 is an apocalyptic number.
It is an amenable number.
340312200212112 is an abundant number, since it is smaller than the sum of its proper divisors (557532753544944).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
340312200212112 is a wasteful number, since it uses less digits than its factorization.
340312200212112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 150847606535 (or 150847606529 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 340312200212112 its reverse (211212002213043), we get a palindrome (551524202425155).
The spelling of 340312200212112 in words is "three hundred forty trillion, three hundred twelve billion, two hundred million, two hundred twelve thousand, one hundred twelve".
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