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340312554611 is a prime number
BaseRepresentation
bin1001111001111000011…
…01010111110001110011
31012112101222002222120022
410330330031113301303
521033430003221421
6420200515034055
733405155662151
oct4747415276163
91175358088508
10340312554611
11121364624237
1255b55b9b92b
1326125886513
14126850303d1
158cbb8347ab
hex4f3c357c73

340312554611 has 2 divisors, whose sum is σ = 340312554612. Its totient is φ = 340312554610.

The previous prime is 340312554587. The next prime is 340312554613. The reversal of 340312554611 is 116455213043.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 340312554611 - 222 = 340308360307 is a prime.

It is a super-2 number, since 2×3403125546112 (a number of 24 digits) contains 22 as substring.

Together with 340312554613, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (340312554613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170156277305 + 170156277306.

It is an arithmetic number, because the mean of its divisors is an integer number (170156277306).

Almost surely, 2340312554611 is an apocalyptic number.

340312554611 is a deficient number, since it is larger than the sum of its proper divisors (1).

340312554611 is an equidigital number, since it uses as much as digits as its factorization.

340312554611 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 340312554611 its reverse (116455213043), we get a palindrome (456767767654).

The spelling of 340312554611 in words is "three hundred forty billion, three hundred twelve million, five hundred fifty-four thousand, six hundred eleven".