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34031953 is a prime number
BaseRepresentation
bin1000000111010…
…0100101010001
32101001000001201
42001310211101
532203010303
63213231201
7562160344
oct201644521
971030051
1034031953
111823478a
12b492501
137087267
14473c45b
152ec381d
hex2074951

34031953 has 2 divisors, whose sum is σ = 34031954. Its totient is φ = 34031952.

The previous prime is 34031951. The next prime is 34031957. The reversal of 34031953 is 35913043.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33269824 + 762129 = 5768^2 + 873^2 .

It is a cyclic number.

It is not a de Polignac number, because 34031953 - 21 = 34031951 is a prime.

Together with 34031951, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (34031951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17015976 + 17015977.

It is an arithmetic number, because the mean of its divisors is an integer number (17015977).

Almost surely, 234031953 is an apocalyptic number.

It is an amenable number.

34031953 is a deficient number, since it is larger than the sum of its proper divisors (1).

34031953 is an equidigital number, since it uses as much as digits as its factorization.

34031953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4860, while the sum is 28.

The square root of 34031953 is about 5833.6911985466. The cubic root of 34031953 is about 324.0626339563.

Adding to 34031953 its reverse (35913043), we get a palindrome (69944996).

It can be divided in two parts, 3403 and 1953, that added together give a triangular number (5356 = T103).

The spelling of 34031953 in words is "thirty-four million, thirty-one thousand, nine hundred fifty-three".