Base | Representation |
---|---|
bin | 11111101101000001… |
… | …010000010000100001 |
3 | 10020212101201012202221 |
4 | 133231001100100201 |
5 | 1024204033100001 |
6 | 23345515111041 |
7 | 2313401163412 |
oct | 375501202041 |
9 | 106771635687 |
10 | 34041300001 |
11 | 13489476595 |
12 | 6720442481 |
13 | 3296716c87 |
14 | 190d06d809 |
15 | d4380b1a1 |
hex | 7ed050421 |
34041300001 has 2 divisors, whose sum is σ = 34041300002. Its totient is φ = 34041300000.
The previous prime is 34041299951. The next prime is 34041300017. The reversal of 34041300001 is 10000314043.
It is an a-pointer prime, because the next prime (34041300017) can be obtained adding 34041300001 to its sum of digits (16).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30924981025 + 3116318976 = 175855^2 + 55824^2 .
It is an emirp because it is prime and its reverse (10000314043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34041300001 - 29 = 34041299489 is a prime.
It is not a weakly prime, because it can be changed into another prime (34041300071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17020650000 + 17020650001.
It is an arithmetic number, because the mean of its divisors is an integer number (17020650001).
Almost surely, 234041300001 is an apocalyptic number.
It is an amenable number.
34041300001 is a deficient number, since it is larger than the sum of its proper divisors (1).
34041300001 is an equidigital number, since it uses as much as digits as its factorization.
34041300001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 34041300001 its reverse (10000314043), we get a palindrome (44041614044).
The spelling of 34041300001 in words is "thirty-four billion, forty-one million, three hundred thousand, one".
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