Base | Representation |
---|---|
bin | 1111011110110010100001… |
… | …10010100111011100011011 |
3 | 11110112111121202102212211112 |
4 | 13233121100302213130123 |
5 | 13430231102123443024 |
6 | 200223132142450535 |
7 | 10112354605333541 |
oct | 757312062473433 |
9 | 143474552385745 |
10 | 34043266234139 |
11 | a935739312818 |
12 | 3999990b93a4b |
13 | 15cc35cba9456 |
14 | 8599ba9a3d91 |
15 | 3e082439e00e |
hex | 1ef650ca771b |
34043266234139 has 2 divisors, whose sum is σ = 34043266234140. Its totient is φ = 34043266234138.
The previous prime is 34043266233997. The next prime is 34043266234141. The reversal of 34043266234139 is 93143266234043.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34043266234139 - 240 = 32943754606363 is a prime.
Together with 34043266234141, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (34043266234739) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17021633117069 + 17021633117070.
It is an arithmetic number, because the mean of its divisors is an integer number (17021633117070).
Almost surely, 234043266234139 is an apocalyptic number.
34043266234139 is a deficient number, since it is larger than the sum of its proper divisors (1).
34043266234139 is an equidigital number, since it uses as much as digits as its factorization.
34043266234139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6718464, while the sum is 50.
The spelling of 34043266234139 in words is "thirty-four trillion, forty-three billion, two hundred sixty-six million, two hundred thirty-four thousand, one hundred thirty-nine".
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