Base | Representation |
---|---|
bin | 110001100010100010110… |
… | …000011100101110000011 |
3 | 110001110012122011200022222 |
4 | 301202202300130232003 |
5 | 421234044221123341 |
6 | 11123533453521255 |
7 | 500645556365144 |
oct | 61424260345603 |
9 | 13043178150288 |
10 | 3404344707971 |
11 | 10a2857922519 |
12 | 46b9501a322b |
13 | 1b904a31215c |
14 | baab20ddacb |
15 | 5d84c7a344b |
hex | 318a2c1cb83 |
3404344707971 has 2 divisors, whose sum is σ = 3404344707972. Its totient is φ = 3404344707970.
The previous prime is 3404344707941. The next prime is 3404344708043. The reversal of 3404344707971 is 1797074434043.
3404344707971 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3404344707971 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (3404344707941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1702172353985 + 1702172353986.
It is an arithmetic number, because the mean of its divisors is an integer number (1702172353986).
Almost surely, 23404344707971 is an apocalyptic number.
3404344707971 is a deficient number, since it is larger than the sum of its proper divisors (1).
3404344707971 is an equidigital number, since it uses as much as digits as its factorization.
3404344707971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7112448, while the sum is 53.
It can be divided in two parts, 340434 and 4707971, that added together give a palindrome (5048405).
The spelling of 3404344707971 in words is "three trillion, four hundred four billion, three hundred forty-four million, seven hundred seven thousand, nine hundred seventy-one".
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