Base | Representation |
---|---|
bin | 110001100011010001101… |
… | …110000100100111100111 |
3 | 110001112020112202110101011 |
4 | 301203101232010213213 |
5 | 421242202422122434 |
6 | 11124144001243051 |
7 | 501004234441465 |
oct | 61432156044747 |
9 | 13045215673334 |
10 | 3405132614119 |
11 | 10a3121653025 |
12 | 46bb30033487 |
13 | 1b914461c402 |
14 | bab489db835 |
15 | 5d896a3be64 |
hex | 318d1b849e7 |
3405132614119 has 2 divisors, whose sum is σ = 3405132614120. Its totient is φ = 3405132614118.
The previous prime is 3405132614069. The next prime is 3405132614161. The reversal of 3405132614119 is 9114162315043.
3405132614119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3405132614119 - 215 = 3405132581351 is a prime.
It is a super-2 number, since 2×34051326141192 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3405132914119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1702566307059 + 1702566307060.
It is an arithmetic number, because the mean of its divisors is an integer number (1702566307060).
Almost surely, 23405132614119 is an apocalyptic number.
3405132614119 is a deficient number, since it is larger than the sum of its proper divisors (1).
3405132614119 is an equidigital number, since it uses as much as digits as its factorization.
3405132614119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 40.
The spelling of 3405132614119 in words is "three trillion, four hundred five billion, one hundred thirty-two million, six hundred fourteen thousand, one hundred nineteen".
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