Base | Representation |
---|---|
bin | 1111011111100100111110… |
… | …10110100101110100010011 |
3 | 11110122002112120000121012211 |
4 | 13233302133112211310103 |
5 | 13431202041121410113 |
6 | 200243412105332551 |
7 | 10114334064326146 |
oct | 757623726456423 |
9 | 143562476017184 |
10 | 34070354091283 |
11 | a946179743814 |
12 | 39a3090797157 |
13 | 1601a88b3b7a3 |
14 | 85b02a35605d |
15 | 3e13ac4dab3d |
hex | 1efc9f5a5d13 |
34070354091283 has 2 divisors, whose sum is σ = 34070354091284. Its totient is φ = 34070354091282.
The previous prime is 34070354091281. The next prime is 34070354091329. The reversal of 34070354091283 is 38219045307043.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 34070354091283 - 21 = 34070354091281 is a prime.
Together with 34070354091281, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (34070354091281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17035177045641 + 17035177045642.
It is an arithmetic number, because the mean of its divisors is an integer number (17035177045642).
Almost surely, 234070354091283 is an apocalyptic number.
34070354091283 is a deficient number, since it is larger than the sum of its proper divisors (1).
34070354091283 is an equidigital number, since it uses as much as digits as its factorization.
34070354091283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2177280, while the sum is 49.
The spelling of 34070354091283 in words is "thirty-four trillion, seventy billion, three hundred fifty-four million, ninety-one thousand, two hundred eighty-three".
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