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34100253413 is a prime number
BaseRepresentation
bin11111110000100010…
…001001001011100101
310021000111122100122122
4133300202021023211
51024314131102123
623355422435325
72315015241302
oct376042111345
9107014570578
1034100253413
1113509782116
126738132b45
1332a59b8755
141916c180a9
15d48aa3bc8
hex7f08892e5

34100253413 has 2 divisors, whose sum is σ = 34100253414. Its totient is φ = 34100253412.

The previous prime is 34100253391. The next prime is 34100253433. The reversal of 34100253413 is 31435200143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32926642849 + 1173610564 = 181457^2 + 34258^2 .

It is an emirp because it is prime and its reverse (31435200143) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34100253413 - 224 = 34083476197 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34100253433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17050126706 + 17050126707.

It is an arithmetic number, because the mean of its divisors is an integer number (17050126707).

Almost surely, 234100253413 is an apocalyptic number.

It is an amenable number.

34100253413 is a deficient number, since it is larger than the sum of its proper divisors (1).

34100253413 is an equidigital number, since it uses as much as digits as its factorization.

34100253413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 34100253413 its reverse (31435200143), we get a palindrome (65535453556).

The spelling of 34100253413 in words is "thirty-four billion, one hundred million, two hundred fifty-three thousand, four hundred thirteen".