341011314241342 has 4 divisors (see below), whose sum is σ = 511516971362016. Its totient is φ = 170505657120670.

The previous prime is 341011314241319. The next prime is 341011314241369. The reversal of 341011314241342 is 243142413110143.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×341011314241342² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 341011314241298 and 341011314241307.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85252828560334 + ... + 85252828560337.

It is an arithmetic number, because the mean of its divisors is an integer number (127879242840504).

Almost surely, 2^{341011314241342} is an apocalyptic number.

341011314241342 is a deficient number, since it is larger than the sum of its proper divisors (170505657120674).

341011314241342 is a wasteful number, since it uses less digits than its factorization.

341011314241342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 170505657120673.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 341011314241342 its reverse (243142413110143), we get a palindrome (584153727351485).

The spelling of 341011314241342 in words is "three hundred forty-one trillion, eleven billion, three hundred fourteen million, two hundred forty-one thousand, three hundred forty-two".