Base | Representation |
---|---|
bin | 1001111011001011111… |
… | …11110101101011110001 |
3 | 1012121012211100022212011 |
4 | 10331211333311223301 |
5 | 21041343443301121 |
6 | 420354242002521 |
7 | 33431431125412 |
oct | 4754577655361 |
9 | 1177184308764 |
10 | 341013650161 |
11 | 121694351748 |
12 | 56110946441 |
13 | 26207bba462 |
14 | 127101b1809 |
15 | 8d0d1717e1 |
hex | 4f65ff5af1 |
341013650161 has 2 divisors, whose sum is σ = 341013650162. Its totient is φ = 341013650160.
The previous prime is 341013650101. The next prime is 341013650179. The reversal of 341013650161 is 161056310143.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 298394525025 + 42619125136 = 546255^2 + 206444^2 .
It is a cyclic number.
It is not a de Polignac number, because 341013650161 - 211 = 341013648113 is a prime.
It is a super-2 number, since 2×3410136501612 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (341013650101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170506825080 + 170506825081.
It is an arithmetic number, because the mean of its divisors is an integer number (170506825081).
Almost surely, 2341013650161 is an apocalyptic number.
It is an amenable number.
341013650161 is a deficient number, since it is larger than the sum of its proper divisors (1).
341013650161 is an equidigital number, since it uses as much as digits as its factorization.
341013650161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 31.
The spelling of 341013650161 in words is "three hundred forty-one billion, thirteen million, six hundred fifty thousand, one hundred sixty-one".
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