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34104122218471 is a prime number
BaseRepresentation
bin1111100000100011111000…
…00101110001011111100111
311110202022200220201012100011
413300101330011301133213
513432230220241442341
6200311114545431051
710116640640555434
oct760217405613747
9143668626635304
1034104122218471
11a959527999548
1239a973563b487
13160500aa8b736
1485c910dd6b8b
153e21d6d36b81
hex1f047c1717e7

34104122218471 has 2 divisors, whose sum is σ = 34104122218472. Its totient is φ = 34104122218470.

The previous prime is 34104122218421. The next prime is 34104122218513. The reversal of 34104122218471 is 17481222140143.

It is a strong prime.

It is an emirp because it is prime and its reverse (17481222140143) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34104122218471 - 215 = 34104122185703 is a prime.

It is a super-3 number, since 3×341041222184713 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34104122218421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17052061109235 + 17052061109236.

It is an arithmetic number, because the mean of its divisors is an integer number (17052061109236).

Almost surely, 234104122218471 is an apocalyptic number.

34104122218471 is a deficient number, since it is larger than the sum of its proper divisors (1).

34104122218471 is an equidigital number, since it uses as much as digits as its factorization.

34104122218471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86016, while the sum is 40.

The spelling of 34104122218471 in words is "thirty-four trillion, one hundred four billion, one hundred twenty-two million, two hundred eighteen thousand, four hundred seventy-one".