Base | Representation |
---|---|
bin | 1111100000100011111000… |
… | …00101110001011111100111 |
3 | 11110202022200220201012100011 |
4 | 13300101330011301133213 |
5 | 13432230220241442341 |
6 | 200311114545431051 |
7 | 10116640640555434 |
oct | 760217405613747 |
9 | 143668626635304 |
10 | 34104122218471 |
11 | a959527999548 |
12 | 39a973563b487 |
13 | 160500aa8b736 |
14 | 85c910dd6b8b |
15 | 3e21d6d36b81 |
hex | 1f047c1717e7 |
34104122218471 has 2 divisors, whose sum is σ = 34104122218472. Its totient is φ = 34104122218470.
The previous prime is 34104122218421. The next prime is 34104122218513. The reversal of 34104122218471 is 17481222140143.
It is a strong prime.
It is an emirp because it is prime and its reverse (17481222140143) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34104122218471 - 215 = 34104122185703 is a prime.
It is a super-3 number, since 3×341041222184713 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34104122218421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17052061109235 + 17052061109236.
It is an arithmetic number, because the mean of its divisors is an integer number (17052061109236).
Almost surely, 234104122218471 is an apocalyptic number.
34104122218471 is a deficient number, since it is larger than the sum of its proper divisors (1).
34104122218471 is an equidigital number, since it uses as much as digits as its factorization.
34104122218471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86016, while the sum is 40.
The spelling of 34104122218471 in words is "thirty-four trillion, one hundred four billion, one hundred twenty-two million, two hundred eighteen thousand, four hundred seventy-one".
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