Base | Representation |
---|---|
bin | 1111100000100100001000… |
… | …00001001011010100001111 |
3 | 11110202100001011222221120021 |
4 | 13300102010001023110033 |
5 | 13432231003314344442 |
6 | 200311140100403011 |
7 | 10116644144264665 |
oct | 760220401132417 |
9 | 143670034887507 |
10 | 34104255231247 |
11 | a959595a88a63 |
12 | 39a97720a6467 |
13 | 160502c4c0616 |
14 | 85c92493cc35 |
15 | 3e21e385ce67 |
hex | 1f048404b50f |
34104255231247 has 2 divisors, whose sum is σ = 34104255231248. Its totient is φ = 34104255231246.
The previous prime is 34104255231187. The next prime is 34104255231251. The reversal of 34104255231247 is 74213255240143.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34104255231247 - 27 = 34104255231119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34104255231287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17052127615623 + 17052127615624.
It is an arithmetic number, because the mean of its divisors is an integer number (17052127615624).
Almost surely, 234104255231247 is an apocalyptic number.
34104255231247 is a deficient number, since it is larger than the sum of its proper divisors (1).
34104255231247 is an equidigital number, since it uses as much as digits as its factorization.
34104255231247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 806400, while the sum is 43.
The spelling of 34104255231247 in words is "thirty-four trillion, one hundred four billion, two hundred fifty-five million, two hundred thirty-one thousand, two hundred forty-seven".
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