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34107440067737 is a prime number
BaseRepresentation
bin1111100000101010000011…
…10110010111010010011001
311110202122021010211101220022
413300111001312113102121
513432304014124131422
6200312424110440225
710120116106041401
oct760250166272231
9143678233741808
1034107440067737
11a95a97a814833
1239aa300803075
13160541928025a
1485cb478db801
153e232d263342
hex1f0541d97499

34107440067737 has 2 divisors, whose sum is σ = 34107440067738. Its totient is φ = 34107440067736.

The previous prime is 34107440067731. The next prime is 34107440067749. The reversal of 34107440067737 is 73776004470143.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22471591257241 + 11635848810496 = 4740421^2 + 3411136^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34107440067737 is a prime.

It is a super-3 number, since 3×341074400677373 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (34107440067731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17053720033868 + 17053720033869.

It is an arithmetic number, because the mean of its divisors is an integer number (17053720033869).

Almost surely, 234107440067737 is an apocalyptic number.

It is an amenable number.

34107440067737 is a deficient number, since it is larger than the sum of its proper divisors (1).

34107440067737 is an equidigital number, since it uses as much as digits as its factorization.

34107440067737 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8297856, while the sum is 53.

The spelling of 34107440067737 in words is "thirty-four trillion, one hundred seven billion, four hundred forty million, sixty-seven thousand, seven hundred thirty-seven".