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341110303011142 = 2728883984355027
BaseRepresentation
bin100110110001111001110111…
…0011100001011000101000110
31122201202211022111212120011121
41031203303232130023011012
5324202222400032324032
63205251524311224154
7131564256204443530
oct11543635634130506
91581684274776147
10341110303011142
1199763081360325
123231156637805a
1311844743178532
146033b80896850
1529680dd7e0a97
hex1363cee70b146

341110303011142 has 16 divisors (see below), whose sum is σ = 584762550900480. Its totient is φ = 146189621998728.

The previous prime is 341110303011047. The next prime is 341110303011193. The reversal of 341110303011142 is 241110303011143.

It is a super-2 number, since 2×3411103030111422 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38133768 + ... + 46221259.

It is an arithmetic number, because the mean of its divisors is an integer number (36547659431280).

Almost surely, 2341110303011142 is an apocalyptic number.

341110303011142 is a deficient number, since it is larger than the sum of its proper divisors (243652247889338).

341110303011142 is a wasteful number, since it uses less digits than its factorization.

341110303011142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84643875.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 341110303011142 its reverse (241110303011143), we get a palindrome (582220606022285).

Subtracting from 341110303011142 its reverse (241110303011143), we obtain a palindrome (99999999999999).

The spelling of 341110303011142 in words is "three hundred forty-one trillion, one hundred ten billion, three hundred three million, eleven thousand, one hundred forty-two".

Divisors: 1 2 7 14 288839 577678 2021873 4043746 84355027 168710054 590485189 1180970378 24365021643653 48730043287306 170555151505571 341110303011142