Base | Representation |
---|---|
bin | 1111100000110101000001… |
… | …11110100110100100100011 |
3 | 11110210012110200201022100012 |
4 | 13300122200332212210203 |
5 | 13432403100220432212 |
6 | 200315240430315135 |
7 | 10120415100304364 |
oct | 760324076464443 |
9 | 143705420638305 |
10 | 34113331030307 |
11 | a962423041141 |
12 | 39ab485658aab |
13 | 1605b4788cb19 |
14 | 85d146045b6b |
15 | 3e257550d922 |
hex | 1f06a0fa6923 |
34113331030307 has 2 divisors, whose sum is σ = 34113331030308. Its totient is φ = 34113331030306.
The previous prime is 34113331030237. The next prime is 34113331030327. The reversal of 34113331030307 is 70303013331143.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34113331030307 - 212 = 34113331026211 is a prime.
It is a super-3 number, since 3×341133310303073 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (34113331030327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17056665515153 + 17056665515154.
It is an arithmetic number, because the mean of its divisors is an integer number (17056665515154).
Almost surely, 234113331030307 is an apocalyptic number.
34113331030307 is a deficient number, since it is larger than the sum of its proper divisors (1).
34113331030307 is an equidigital number, since it uses as much as digits as its factorization.
34113331030307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20412, while the sum is 32.
The spelling of 34113331030307 in words is "thirty-four trillion, one hundred thirteen billion, three hundred thirty-one million, thirty thousand, three hundred seven".
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