Base | Representation |
---|---|
bin | 110001101001001001110… |
… | …110010011011011010111 |
3 | 110002010112022212112111020 |
4 | 301221021312103123113 |
5 | 421343113402131033 |
6 | 11131110103012223 |
7 | 501316511045115 |
oct | 61511166233327 |
9 | 13063468775436 |
10 | 3411443005143 |
11 | 10a586a705218 |
12 | 4711b143a073 |
13 | 1b990bab37b4 |
14 | bb186b26ab5 |
15 | 5db15a376b3 |
hex | 31a49d936d7 |
3411443005143 has 24 divisors (see below), whose sum is σ = 4715166538368. Its totient is φ = 2193853446000.
The previous prime is 3411443005127. The next prime is 3411443005177. The reversal of 3411443005143 is 3415003441143.
It is not a de Polignac number, because 3411443005143 - 24 = 3411443005127 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3411443000143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1005793 + ... + 2799018.
It is an arithmetic number, because the mean of its divisors is an integer number (196465272432).
Almost surely, 23411443005143 is an apocalyptic number.
3411443005143 is a deficient number, since it is larger than the sum of its proper divisors (1303723533225).
3411443005143 is a wasteful number, since it uses less digits than its factorization.
3411443005143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3805187 (or 3805156 counting only the distinct ones).
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 3411443005143 its reverse (3415003441143), we get a palindrome (6826446446286).
The spelling of 3411443005143 in words is "three trillion, four hundred eleven billion, four hundred forty-three million, five thousand, one hundred forty-three".
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