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34120039895173 is a prime number
BaseRepresentation
bin1111100001000001100001…
…10110111001000010000101
311110210211210020121221210201
413300200300312321002011
513433010320203121143
6200322310244450501
710121043252565231
oct760406066710205
9143724706557721
1034120039895173
11a965256016661
1239b08383a9a31
13160667677cc4b
1485d5c10595c1
153e28194ba64d
hex1f0830db9085

34120039895173 has 2 divisors, whose sum is σ = 34120039895174. Its totient is φ = 34120039895172.

The previous prime is 34120039895101. The next prime is 34120039895209. The reversal of 34120039895173 is 37159893002143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33484484950084 + 635554945089 = 5786578^2 + 797217^2 .

It is a cyclic number.

It is not a de Polignac number, because 34120039895173 - 225 = 34120006340741 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34120039845173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17060019947586 + 17060019947587.

It is an arithmetic number, because the mean of its divisors is an integer number (17060019947587).

Almost surely, 234120039895173 is an apocalyptic number.

It is an amenable number.

34120039895173 is a deficient number, since it is larger than the sum of its proper divisors (1).

34120039895173 is an equidigital number, since it uses as much as digits as its factorization.

34120039895173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4898880, while the sum is 55.

The spelling of 34120039895173 in words is "thirty-four trillion, one hundred twenty billion, thirty-nine million, eight hundred ninety-five thousand, one hundred seventy-three".