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34126344362093 is a prime number
BaseRepresentation
bin1111100001001101010001…
…01000100001100001101101
311110211110001121121001120112
413300212220220201201231
513433111223124041333
6200325232015225405
710121355424636244
oct760465050414155
9143743047531515
1034126344362093
11a9679a07a19a5
1239b1ab7818265
13160713c94ba49
1485da1c48195b
153e2a87be5948
hex1f09a8a2186d

34126344362093 has 2 divisors, whose sum is σ = 34126344362094. Its totient is φ = 34126344362092.

The previous prime is 34126344362069. The next prime is 34126344362147. The reversal of 34126344362093 is 39026344362143.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22000996632484 + 12125347729609 = 4690522^2 + 3482147^2 .

It is a cyclic number.

It is not a de Polignac number, because 34126344362093 - 228 = 34126075926637 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34126344362053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17063172181046 + 17063172181047.

It is an arithmetic number, because the mean of its divisors is an integer number (17063172181047).

Almost surely, 234126344362093 is an apocalyptic number.

It is an amenable number.

34126344362093 is a deficient number, since it is larger than the sum of its proper divisors (1).

34126344362093 is an equidigital number, since it uses as much as digits as its factorization.

34126344362093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6718464, while the sum is 50.

Adding to 34126344362093 its sum of digits (50), we get a palindrome (34126344362143).

The spelling of 34126344362093 in words is "thirty-four trillion, one hundred twenty-six billion, three hundred forty-four million, three hundred sixty-two thousand, ninety-three".