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341303252550401 is a prime number
BaseRepresentation
bin100110110011010011101101…
…1001000010000001100000001
31122202110021100111110201202102
41031212213123020100030001
5324213403030123103101
63205520314421400145
7131614226524454441
oct11546473310201401
91582407314421672
10341303252550401
1199827995341a69
1232342a34869055
13118599b28a473b
14603d246444121
15296d132cce86b
hex13669db210301

341303252550401 has 2 divisors, whose sum is σ = 341303252550402. Its totient is φ = 341303252550400.

The previous prime is 341303252550397. The next prime is 341303252550413. The reversal of 341303252550401 is 104055252303143.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 321515345860801 + 19787906689600 = 17930849^2 + 4448360^2 .

It is a cyclic number.

It is not a de Polignac number, because 341303252550401 - 22 = 341303252550397 is a prime.

It is a super-2 number, since 2×3413032525504012 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (341303252510401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170651626275200 + 170651626275201.

It is an arithmetic number, because the mean of its divisors is an integer number (170651626275201).

Almost surely, 2341303252550401 is an apocalyptic number.

It is an amenable number.

341303252550401 is a deficient number, since it is larger than the sum of its proper divisors (1).

341303252550401 is an equidigital number, since it uses as much as digits as its factorization.

341303252550401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 38.

The spelling of 341303252550401 in words is "three hundred forty-one trillion, three hundred three billion, two hundred fifty-two million, five hundred fifty thousand, four hundred one".