Base | Representation |
---|---|
bin | 100110110011011000110001… |
… | …0011110110001111001100111 |
3 | 1122202111022101101220201010011 |
4 | 1031212301202132301321213 |
5 | 324214042301002030112 |
6 | 3205525312233311051 |
7 | 131615062623441442 |
oct | 11546614236617147 |
9 | 1582438341821104 |
10 | 341314113314407 |
11 | 99831558a1a792 |
12 | 32344b65b65487 |
13 | 1185aa239cb70c |
14 | 603d996a2c659 |
15 | 296d56b518aa7 |
hex | 1366c627b1e67 |
341314113314407 has 2 divisors, whose sum is σ = 341314113314408. Its totient is φ = 341314113314406.
The previous prime is 341314113314399. The next prime is 341314113314441. The reversal of 341314113314407 is 704413311413143.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 341314113314407 - 23 = 341314113314399 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 341314113314407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (341314113314467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170657056657203 + 170657056657204.
It is an arithmetic number, because the mean of its divisors is an integer number (170657056657204).
Almost surely, 2341314113314407 is an apocalyptic number.
341314113314407 is a deficient number, since it is larger than the sum of its proper divisors (1).
341314113314407 is an equidigital number, since it uses as much as digits as its factorization.
341314113314407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 40.
The spelling of 341314113314407 in words is "three hundred forty-one trillion, three hundred fourteen billion, one hundred thirteen million, three hundred fourteen thousand, four hundred seven".
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