341325101523143 has 8 divisors (see below), whose sum is σ = 341381266934400. Its totient is φ = 341268937640568.

The previous prime is 341325101523139. The next prime is 341325101523149.

It is a happy number.

341325101523143 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 341325101523143 - 2² = 341325101523139 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 341325101523097 and 341325101523106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (341325101523149) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 499534988 + ... + 500217806.

It is an arithmetic number, because the mean of its divisors is an integer number (42672658366800).

Almost surely, 2^{341325101523143} is an apocalyptic number.

341325101523143 is a deficient number, since it is larger than the sum of its proper divisors (56165411257).

341325101523143 is an equidigital number, since it uses as much as digits as its factorization.

341325101523143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 764341.

The product of its (nonzero) digits is 129600, while the sum is 38.

It can be divided in two parts, 34132510 and 1523143, that added together give a palindrome (35655653).

The spelling of 341325101523143 in words is "three hundred forty-one trillion, three hundred twenty-five billion, one hundred one million, five hundred twenty-three thousand, one hundred forty-three".