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3413411341381 is a prime number
BaseRepresentation
bin110001101010111111001…
…010111010010001000101
3110002022121111122101012101
4301222333022322101011
5421411131300411011
611132033255152101
7501416341451536
oct61527712722105
913068544571171
103413411341381
1110a668a795388
12471660675631
131b9b638227b2
14bb2d22dc68d
155dbcd7432c1
hex31abf2ba445

3413411341381 has 2 divisors, whose sum is σ = 3413411341382. Its totient is φ = 3413411341380.

The previous prime is 3413411341313. The next prime is 3413411341391. The reversal of 3413411341381 is 1831431143143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2980698660900 + 432712680481 = 1726470^2 + 657809^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3413411341381 is a prime.

It is a super-2 number, since 2×34134113413812 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3413411341381.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3413411341391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706705670690 + 1706705670691.

It is an arithmetic number, because the mean of its divisors is an integer number (1706705670691).

Almost surely, 23413411341381 is an apocalyptic number.

It is an amenable number.

3413411341381 is a deficient number, since it is larger than the sum of its proper divisors (1).

3413411341381 is an equidigital number, since it uses as much as digits as its factorization.

3413411341381 is an evil number, because the sum of its binary digits is even.

The product of its digits is 41472, while the sum is 37.

The spelling of 3413411341381 in words is "three trillion, four hundred thirteen billion, four hundred eleven million, three hundred forty-one thousand, three hundred eighty-one".