Base | Representation |
---|---|
bin | 110001101011000000111… |
… | …000010111001001111011 |
3 | 110002022200111122002020212 |
4 | 301223000320113021323 |
5 | 421411211122032103 |
6 | 11132040202141335 |
7 | 501420140362001 |
oct | 61530070271173 |
9 | 13068614562225 |
10 | 3413440033403 |
11 | 10a66a4a020a4 |
12 | 47166a1b184b |
13 | 1b9b6975a31a |
14 | bb2d604aa71 |
15 | 5dbd100e7d8 |
hex | 31ac0e1727b |
3413440033403 has 2 divisors, whose sum is σ = 3413440033404. Its totient is φ = 3413440033402.
The previous prime is 3413440033387. The next prime is 3413440033427. The reversal of 3413440033403 is 3043300443143.
3413440033403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3413440033403 - 24 = 3413440033387 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3413440033403.
It is not a weakly prime, because it can be changed into another prime (3413440033453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706720016701 + 1706720016702.
It is an arithmetic number, because the mean of its divisors is an integer number (1706720016702).
Almost surely, 23413440033403 is an apocalyptic number.
3413440033403 is a deficient number, since it is larger than the sum of its proper divisors (1).
3413440033403 is an equidigital number, since it uses as much as digits as its factorization.
3413440033403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 32.
Adding to 3413440033403 its reverse (3043300443143), we get a palindrome (6456740476546).
The spelling of 3413440033403 in words is "three trillion, four hundred thirteen billion, four hundred forty million, thirty-three thousand, four hundred three".
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