Base | Representation |
---|---|
bin | 1001111011110011011… |
… | …01100110010110101101 |
3 | 1012122001212201211022102 |
4 | 10331321231212112231 |
5 | 21043033132204401 |
6 | 420451135224445 |
7 | 33442555432016 |
oct | 4757155462655 |
9 | 1178055654272 |
10 | 341344413101 |
11 | 12184402784a |
12 | 561a3678125 |
13 | 2625b599583 |
14 | 127420b200d |
15 | 8d2c20a56b |
hex | 4f79b665ad |
341344413101 has 2 divisors, whose sum is σ = 341344413102. Its totient is φ = 341344413100.
The previous prime is 341344413079. The next prime is 341344413119. The reversal of 341344413101 is 101314443143.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 222750961225 + 118593451876 = 471965^2 + 344374^2 .
It is a cyclic number.
It is not a de Polignac number, because 341344413101 - 234 = 324164543917 is a prime.
It is a super-2 number, since 2×3413444131012 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (341344413001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170672206550 + 170672206551.
It is an arithmetic number, because the mean of its divisors is an integer number (170672206551).
Almost surely, 2341344413101 is an apocalyptic number.
It is an amenable number.
341344413101 is a deficient number, since it is larger than the sum of its proper divisors (1).
341344413101 is an equidigital number, since it uses as much as digits as its factorization.
341344413101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 341344413101 its reverse (101314443143), we get a palindrome (442658856244).
The spelling of 341344413101 in words is "three hundred forty-one billion, three hundred forty-four million, four hundred thirteen thousand, one hundred one".
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