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34134520612333 is a prime number
BaseRepresentation
bin1111100001011100011111…
…11110011100010111101101
311110212020011102122121100111
413300232033332130113231
513433224444234043313
6200333103212500021
710122065145626431
oct760561776342755
9143766142577314
1034134520612333
11a9704070007a9
1239b35b9a7a611
131607b4385203b
148601963089c1
153e2db590843d
hex1f0b8ff9c5ed

34134520612333 has 2 divisors, whose sum is σ = 34134520612334. Its totient is φ = 34134520612332.

The previous prime is 34134520612249. The next prime is 34134520612391. The reversal of 34134520612333 is 33321602543143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32511640802404 + 1622879809929 = 5701898^2 + 1273923^2 .

It is an emirp because it is prime and its reverse (33321602543143) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34134520612333 - 217 = 34134520481261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34134520642333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17067260306166 + 17067260306167.

It is an arithmetic number, because the mean of its divisors is an integer number (17067260306167).

Almost surely, 234134520612333 is an apocalyptic number.

It is an amenable number.

34134520612333 is a deficient number, since it is larger than the sum of its proper divisors (1).

34134520612333 is an equidigital number, since it uses as much as digits as its factorization.

34134520612333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 466560, while the sum is 40.

The spelling of 34134520612333 in words is "thirty-four trillion, one hundred thirty-four billion, five hundred twenty million, six hundred twelve thousand, three hundred thirty-three".