Base | Representation |
---|---|
bin | 1111100001011101100111… |
… | …10100101011101011111011 |
3 | 11110212021201100022221221221 |
4 | 13300232303310223223323 |
5 | 13433232212220032103 |
6 | 200333243015212511 |
7 | 10122116100624556 |
oct | 760566364535373 |
9 | 143767640287857 |
10 | 34135122033403 |
11 | a97069553a306 |
12 | 39b3747377137 |
13 | 1607c0b3276b1 |
14 | 86021214169d |
15 | 3e2ded6071bd |
hex | 1f0bb3d2bafb |
34135122033403 has 2 divisors, whose sum is σ = 34135122033404. Its totient is φ = 34135122033402.
The previous prime is 34135122033371. The next prime is 34135122033413. The reversal of 34135122033403 is 30433022153143.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34135122033403 - 25 = 34135122033371 is a prime.
It is a super-2 number, since 2×341351220334032 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (34135122033413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17067561016701 + 17067561016702.
It is an arithmetic number, because the mean of its divisors is an integer number (17067561016702).
Almost surely, 234135122033403 is an apocalyptic number.
34135122033403 is a deficient number, since it is larger than the sum of its proper divisors (1).
34135122033403 is an equidigital number, since it uses as much as digits as its factorization.
34135122033403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 34.
Adding to 34135122033403 its reverse (30433022153143), we get a palindrome (64568144186546).
The spelling of 34135122033403 in words is "thirty-four trillion, one hundred thirty-five billion, one hundred twenty-two million, thirty-three thousand, four hundred three".
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