34135152131 has 2 divisors, whose sum is σ = 34135152132. Its totient is φ = 34135152130.

The previous prime is 34135152101. The next prime is 34135152133. The reversal of 34135152131 is 13125153143.

It is a strong prime.

It is an emirp because it is prime and its reverse (13125153143) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34135152131 - 2⁶ = 34135152067 is a prime.

It is a super-2 number, since 2×34135152131² (a number of 22 digits) contains 22 as substring.

Together with 34135152133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 34135152094 and 34135152103.

It is not a weakly prime, because it can be changed into another prime (34135152133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17067576065 + 17067576066.

It is an arithmetic number, because the mean of its divisors is an integer number (17067576066).

Almost surely, 2^34135152131 is an apocalyptic number.

34135152131 is a deficient number, since it is larger than the sum of its proper divisors (1).

34135152131 is an equidigital number, since it uses as much as digits as its factorization.

34135152131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5400, while the sum is 29.

The spelling of 34135152131 in words is "thirty-four billion, one hundred thirty-five million, one hundred fifty-two thousand, one hundred thirty-one".