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34140411433 is a prime number
BaseRepresentation
bin11111110010111011…
…010101011000101001
310021010022012121002201
4133302323111120221
51024404421131213
623403415300201
72316013465132
oct376273253051
9107108177081
1034140411433
111352a410467
12674967a661
1332b11091ab
14191c2acc89
15d4c3876dd
hex7f2ed5629

34140411433 has 2 divisors, whose sum is σ = 34140411434. Its totient is φ = 34140411432.

The previous prime is 34140411413. The next prime is 34140411493. The reversal of 34140411433 is 33411404143.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17164406169 + 16976005264 = 131013^2 + 130292^2 .

It is a cyclic number.

It is not a de Polignac number, because 34140411433 - 221 = 34138314281 is a prime.

It is a super-2 number, since 2×341404114332 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (34140411413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17070205716 + 17070205717.

It is an arithmetic number, because the mean of its divisors is an integer number (17070205717).

Almost surely, 234140411433 is an apocalyptic number.

It is an amenable number.

34140411433 is a deficient number, since it is larger than the sum of its proper divisors (1).

34140411433 is an equidigital number, since it uses as much as digits as its factorization.

34140411433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 34140411433 its reverse (33411404143), we get a palindrome (67551815576).

The spelling of 34140411433 in words is "thirty-four billion, one hundred forty million, four hundred eleven thousand, four hundred thirty-three".