Base | Representation |
---|---|
bin | 1001111011111011010… |
… | …01011110011111110001 |
3 | 1012122020110222101211121 |
4 | 10331331221132133301 |
5 | 21043202033104301 |
6 | 420501454342241 |
7 | 33444316603534 |
oct | 4757551363761 |
9 | 1178213871747 |
10 | 341410441201 |
11 | 121878325725 |
12 | 562017ba981 |
13 | 2626c17725b |
14 | 1274ab7ca1b |
15 | 8d32dee3a1 |
hex | 4f7da5e7f1 |
341410441201 has 2 divisors, whose sum is σ = 341410441202. Its totient is φ = 341410441200.
The previous prime is 341410441189. The next prime is 341410441217. The reversal of 341410441201 is 102144014143.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 294332290576 + 47078150625 = 542524^2 + 216975^2 .
It is a cyclic number.
It is not a de Polignac number, because 341410441201 - 221 = 341408344049 is a prime.
It is a super-2 number, since 2×3414104412012 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (341410441231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170705220600 + 170705220601.
It is an arithmetic number, because the mean of its divisors is an integer number (170705220601).
Almost surely, 2341410441201 is an apocalyptic number.
It is an amenable number.
341410441201 is a deficient number, since it is larger than the sum of its proper divisors (1).
341410441201 is an equidigital number, since it uses as much as digits as its factorization.
341410441201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 341410441201 its reverse (102144014143), we get a palindrome (443554455344).
The spelling of 341410441201 in words is "three hundred forty-one billion, four hundred ten million, four hundred forty-one thousand, two hundred one".
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