341414133131 has 2 divisors, whose sum is σ = 341414133132. Its totient is φ = 341414133130.

The previous prime is 341414133113. The next prime is 341414133133. The reversal of 341414133131 is 131331414143.

Together with previous prime (341414133113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-341414133131 is a prime.

It is a super-2 number, since 2×341414133131² (a number of 24 digits) contains 22 as substring.

Together with 341414133133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 341414133094 and 341414133103.

It is not a weakly prime, because it can be changed into another prime (341414133133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170707066565 + 170707066566.

It is an arithmetic number, because the mean of its divisors is an integer number (170707066566).

Almost surely, 2^341414133131 is an apocalyptic number.

341414133131 is a deficient number, since it is larger than the sum of its proper divisors (1).

341414133131 is an equidigital number, since it uses as much as digits as its factorization.

341414133131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5184, while the sum is 29.

Adding to 341414133131 its reverse (131331414143), we get a palindrome (472745547274).

The spelling of 341414133131 in words is "three hundred forty-one billion, four hundred fourteen million, one hundred thirty-three thousand, one hundred thirty-one".