Base | Representation |
---|---|
bin | 110001101011101110010… |
… | …011000101000101111111 |
3 | 110002101122121102121102112 |
4 | 301223232103011011333 |
5 | 421414241203341111 |
6 | 11132243542044235 |
7 | 501445052161016 |
oct | 61535623050577 |
9 | 13071577377375 |
10 | 3414202012031 |
11 | 10a6a560339a8 |
12 | 47184141967b |
13 | 1b9c5b58a155 |
14 | bb369319a7d |
15 | 5dc27d75e8b |
hex | 31aee4c517f |
3414202012031 has 2 divisors, whose sum is σ = 3414202012032. Its totient is φ = 3414202012030.
The previous prime is 3414202012009. The next prime is 3414202012057. The reversal of 3414202012031 is 1302102024143.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3414202012031 - 222 = 3414197817727 is a prime.
It is a super-2 number, since 2×34142020120312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3414202011988 and 3414202012006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3414202012061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1707101006015 + 1707101006016.
It is an arithmetic number, because the mean of its divisors is an integer number (1707101006016).
Almost surely, 23414202012031 is an apocalyptic number.
3414202012031 is a deficient number, since it is larger than the sum of its proper divisors (1).
3414202012031 is an equidigital number, since it uses as much as digits as its factorization.
3414202012031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 3414202012031 its reverse (1302102024143), we get a palindrome (4716304036174).
The spelling of 3414202012031 in words is "three trillion, four hundred fourteen billion, two hundred two million, twelve thousand, thirty-one".
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