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3414510360491 is a prime number
BaseRepresentation
bin110001101100000000101…
…011010101011110101011
3110002102110002122022222212
4301230000223111132223
5421420404123013431
611132334315035335
7501455515121066
oct61540053253653
913072402568885
103414510360491
1110a70a409a73a
1247190873bb4b
131b9caa41bb69
14bb3982638dd
155dc44e8372b
hex31b00ad57ab

3414510360491 has 2 divisors, whose sum is σ = 3414510360492. Its totient is φ = 3414510360490.

The previous prime is 3414510360479. The next prime is 3414510360493. The reversal of 3414510360491 is 1940630154143.

3414510360491 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (1940630154143) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3414510360491 - 218 = 3414510098347 is a prime.

It is a super-2 number, since 2×34145103604912 (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 3414510360493, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3414510360493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1707255180245 + 1707255180246.

It is an arithmetic number, because the mean of its divisors is an integer number (1707255180246).

Almost surely, 23414510360491 is an apocalyptic number.

3414510360491 is a deficient number, since it is larger than the sum of its proper divisors (1).

3414510360491 is an equidigital number, since it uses as much as digits as its factorization.

3414510360491 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 41.

The spelling of 3414510360491 in words is "three trillion, four hundred fourteen billion, five hundred ten million, three hundred sixty thousand, four hundred ninety-one".