Base | Representation |
---|---|
bin | 1001111100000000011… |
… | …01001011010010000101 |
3 | 1012122100110201121021212 |
4 | 10332000031023102011 |
5 | 21043244024312432 |
6 | 420510030221205 |
7 | 33445350423221 |
oct | 4760015132205 |
9 | 1178313647255 |
10 | 341453354117 |
11 | 12189a575847 |
12 | 56214054805 |
13 | 26278020905 |
14 | 1275274d781 |
15 | 8d36a792b2 |
hex | 4f8034b485 |
341453354117 has 2 divisors, whose sum is σ = 341453354118. Its totient is φ = 341453354116.
The previous prime is 341453354057. The next prime is 341453354171. The reversal of 341453354117 is 711453354143.
Together with next prime (341453354171) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 336770141761 + 4683212356 = 580319^2 + 68434^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-341453354117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (341453354317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170726677058 + 170726677059.
It is an arithmetic number, because the mean of its divisors is an integer number (170726677059).
Almost surely, 2341453354117 is an apocalyptic number.
It is an amenable number.
341453354117 is a deficient number, since it is larger than the sum of its proper divisors (1).
341453354117 is an equidigital number, since it uses as much as digits as its factorization.
341453354117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 302400, while the sum is 41.
The spelling of 341453354117 in words is "three hundred forty-one billion, four hundred fifty-three million, three hundred fifty-four thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •