Base | Representation |
---|---|
bin | 110001101100110000100… |
… | …001100011000110010001 |
3 | 110002111112001010210020021 |
4 | 301230300201203012101 |
5 | 421424030123214301 |
6 | 11132550112343441 |
7 | 501514433241031 |
oct | 61546041430621 |
9 | 13074461123207 |
10 | 3415313101201 |
11 | 10a7476232711 |
12 | 471ab1544b81 |
13 | 1ba0a7821371 |
14 | bb432b038c1 |
15 | 5dc9069c8a1 |
hex | 31b30863191 |
3415313101201 has 2 divisors, whose sum is σ = 3415313101202. Its totient is φ = 3415313101200.
The previous prime is 3415313101171. The next prime is 3415313101283. The reversal of 3415313101201 is 1021013135143.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1979018714176 + 1436294387025 = 1406776^2 + 1198455^2 .
It is a cyclic number.
It is not a de Polignac number, because 3415313101201 - 211 = 3415313099153 is a prime.
It is not a weakly prime, because it can be changed into another prime (3415313101801) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1707656550600 + 1707656550601.
It is an arithmetic number, because the mean of its divisors is an integer number (1707656550601).
Almost surely, 23415313101201 is an apocalyptic number.
It is an amenable number.
3415313101201 is a deficient number, since it is larger than the sum of its proper divisors (1).
3415313101201 is an equidigital number, since it uses as much as digits as its factorization.
3415313101201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 3415313101201 its reverse (1021013135143), we get a palindrome (4436326236344).
The spelling of 3415313101201 in words is "three trillion, four hundred fifteen billion, three hundred thirteen million, one hundred one thousand, two hundred one".
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