34153411134343 has 2 divisors, whose sum is σ = 34153411134344. Its totient is φ = 34153411134342.

The previous prime is 34153411134317. The next prime is 34153411134373. The reversal of 34153411134343 is 34343111435143.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-34153411134343 is a prime.

It is a super-2 number, since 2×34153411134343² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34153411134296 and 34153411134305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34153411134313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17076705567171 + 17076705567172.

It is an arithmetic number, because the mean of its divisors is an integer number (17076705567172).

Almost surely, 2^{34153411134343} is an apocalyptic number.

34153411134343 is a deficient number, since it is larger than the sum of its proper divisors (1).

34153411134343 is an equidigital number, since it uses as much as digits as its factorization.

34153411134343 is an evil number, because the sum of its binary digits is even.

The product of its digits is 311040, while the sum is 40.

Adding to 34153411134343 its reverse (34343111435143), we get a palindrome (68496522569486).

The spelling of 34153411134343 in words is "thirty-four trillion, one hundred fifty-three billion, four hundred eleven million, one hundred thirty-four thousand, three hundred forty-three".