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34200164113 is a prime number
BaseRepresentation
bin11111110110011111…
…010001011100010001
310021021110122100100221
4133312133101130101
51030020220222423
623413352113041
72320340412163
oct376637213421
9107243570327
1034200164113
1113560112545
126765695781
1332c05ca6cb
1419261c4933
15d5273be5d
hex7f67d1711

34200164113 has 2 divisors, whose sum is σ = 34200164114. Its totient is φ = 34200164112.

The previous prime is 34200164093. The next prime is 34200164129. The reversal of 34200164113 is 31146100243.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19351035664 + 14849128449 = 139108^2 + 121857^2 .

It is a cyclic number.

It is not a de Polignac number, because 34200164113 - 213 = 34200155921 is a prime.

It is a super-2 number, since 2×342001641132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (34200144113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17100082056 + 17100082057.

It is an arithmetic number, because the mean of its divisors is an integer number (17100082057).

Almost surely, 234200164113 is an apocalyptic number.

It is an amenable number.

34200164113 is a deficient number, since it is larger than the sum of its proper divisors (1).

34200164113 is an equidigital number, since it uses as much as digits as its factorization.

34200164113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 34200164113 its reverse (31146100243), we get a palindrome (65346264356).

The spelling of 34200164113 in words is "thirty-four billion, two hundred million, one hundred sixty-four thousand, one hundred thirteen".