Base | Representation |
---|---|
bin | 1100101111011010… |
… | …1100110110000011 |
3 | 22211100112210211021 |
4 | 3023312230312003 |
5 | 24001022124212 |
6 | 1323212530311 |
7 | 150516330511 |
oct | 31366546603 |
9 | 8740483737 |
10 | 3420114307 |
11 | 14a5624555 |
12 | 7b5480997 |
13 | 42674929c |
14 | 2463254b1 |
15 | 1503cc307 |
hex | cbdacd83 |
3420114307 has 2 divisors, whose sum is σ = 3420114308. Its totient is φ = 3420114306.
The previous prime is 3420114223. The next prime is 3420114311. The reversal of 3420114307 is 7034110243.
It is a strong prime.
It is an emirp because it is prime and its reverse (7034110243) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3420114307 is a prime.
It is not a weakly prime, because it can be changed into another prime (3420114107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1710057153 + 1710057154.
It is an arithmetic number, because the mean of its divisors is an integer number (1710057154).
Almost surely, 23420114307 is an apocalyptic number.
3420114307 is a deficient number, since it is larger than the sum of its proper divisors (1).
3420114307 is an equidigital number, since it uses as much as digits as its factorization.
3420114307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
The square root of 3420114307 is about 58481.7433649169. The cubic root of 3420114307 is about 1506.6540398923.
The spelling of 3420114307 in words is "three billion, four hundred twenty million, one hundred fourteen thousand, three hundred seven".
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