Base | Representation |
---|---|
bin | 1001111101001000000… |
… | …00100001000010011101 |
3 | 1012200220022222100022011 |
4 | 10332210000201002131 |
5 | 21101011311441013 |
6 | 421045404351221 |
7 | 33466263104425 |
oct | 4764400410235 |
9 | 1180808870264 |
10 | 342054015133 |
11 | 122078635306 |
12 | 56361245511 |
13 | 263425bb32c |
14 | 127ac429485 |
15 | 8d6e677c3d |
hex | 4fa402109d |
342054015133 has 2 divisors, whose sum is σ = 342054015134. Its totient is φ = 342054015132.
The previous prime is 342054015113. The next prime is 342054015139. The reversal of 342054015133 is 331510450243.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 243519549529 + 98534465604 = 493477^2 + 313902^2 .
It is a cyclic number.
It is not a de Polignac number, because 342054015133 - 25 = 342054015101 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 342054015095 and 342054015104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (342054015139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171027007566 + 171027007567.
It is an arithmetic number, because the mean of its divisors is an integer number (171027007567).
Almost surely, 2342054015133 is an apocalyptic number.
It is an amenable number.
342054015133 is a deficient number, since it is larger than the sum of its proper divisors (1).
342054015133 is an equidigital number, since it uses as much as digits as its factorization.
342054015133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 342054015133 its reverse (331510450243), we get a palindrome (673564465376).
The spelling of 342054015133 in words is "three hundred forty-two billion, fifty-four million, fifteen thousand, one hundred thirty-three".
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