Base | Representation |
---|---|
bin | 1111100011101001010011… |
… | …00010011101110010101111 |
3 | 11111010110021111002011112010 |
4 | 13301310221202131302233 |
5 | 13440444302010212143 |
6 | 200431524102012303 |
7 | 10130412311060631 |
oct | 761645142356257 |
9 | 144113244064463 |
10 | 34210111413423 |
11 | a99a477045440 |
12 | 3a06195117093 |
13 | 1611ccc352aca |
14 | 863ac7652a51 |
15 | 3e4d3bc72a33 |
hex | 1f1d2989dcaf |
34210111413423 has 32 divisors (see below), whose sum is σ = 51005273727744. Its totient is φ = 20215228320000.
The previous prime is 34210111413391. The next prime is 34210111413451. The reversal of 34210111413423 is 32431411101243.
It is not a de Polignac number, because 34210111413423 - 25 = 34210111413391 is a prime.
It is a super-2 number, since 2×342101114134232 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34210111412423) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5605873 + ... + 9992298.
It is an arithmetic number, because the mean of its divisors is an integer number (1593914803992).
Almost surely, 234210111413423 is an apocalyptic number.
34210111413423 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
34210111413423 is a deficient number, since it is larger than the sum of its proper divisors (16795162314321).
34210111413423 is a wasteful number, since it uses less digits than its factorization.
34210111413423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15599847.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 34210111413423 its reverse (32431411101243), we get a palindrome (66641522514666).
The spelling of 34210111413423 in words is "thirty-four trillion, two hundred ten billion, one hundred eleven million, four hundred thirteen thousand, four hundred twenty-three".
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