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34212443122433 is a prime number
BaseRepresentation
bin1111100011101101101001…
…00001001110101100000001
311111010200021222121020222002
413301312310201032230001
513441014040414404213
6200432551314353345
710130524143216242
oct761666441165401
9144120258536862
1034212443122433
11a9a0463253984
123a06725b8b855
1316122b144aa94
14863c691b6cc9
153e4e26809658
hex1f1db484eb01

34212443122433 has 2 divisors, whose sum is σ = 34212443122434. Its totient is φ = 34212443122432.

The previous prime is 34212443122387. The next prime is 34212443122489. The reversal of 34212443122433 is 33422134421243.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22222484249329 + 11989958873104 = 4714073^2 + 3462652^2 .

It is an emirp because it is prime and its reverse (33422134421243) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34212443122433 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (34212443122133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17106221561216 + 17106221561217.

It is an arithmetic number, because the mean of its divisors is an integer number (17106221561217).

Almost surely, 234212443122433 is an apocalyptic number.

It is an amenable number.

34212443122433 is a deficient number, since it is larger than the sum of its proper divisors (1).

34212443122433 is an equidigital number, since it uses as much as digits as its factorization.

34212443122433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 331776, while the sum is 38.

Adding to 34212443122433 its reverse (33422134421243), we get a palindrome (67634577543676).

The spelling of 34212443122433 in words is "thirty-four trillion, two hundred twelve billion, four hundred forty-three million, one hundred twenty-two thousand, four hundred thirty-three".