Base | Representation |
---|---|
bin | 1111100011101111101001… |
… | …10110010111110100110111 |
3 | 11111010210002012110120122212 |
4 | 13301313310312113310313 |
5 | 13441023243214003321 |
6 | 200433250351244035 |
7 | 10130562660042524 |
oct | 761676466276467 |
9 | 144123065416585 |
10 | 34213522406711 |
11 | a9a09674aa15a |
12 | 3a0698751961b |
13 | 1612423c2762b |
14 | 863d2c68214b |
15 | 3e4e8b44c55b |
hex | 1f1df4d97d37 |
34213522406711 has 2 divisors, whose sum is σ = 34213522406712. Its totient is φ = 34213522406710.
The previous prime is 34213522406617. The next prime is 34213522406759. The reversal of 34213522406711 is 11760422531243.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34213522406711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34213522406111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17106761203355 + 17106761203356.
It is an arithmetic number, because the mean of its divisors is an integer number (17106761203356).
Almost surely, 234213522406711 is an apocalyptic number.
34213522406711 is a deficient number, since it is larger than the sum of its proper divisors (1).
34213522406711 is an equidigital number, since it uses as much as digits as its factorization.
34213522406711 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 41.
Adding to 34213522406711 its reverse (11760422531243), we get a palindrome (45973944937954).
The spelling of 34213522406711 in words is "thirty-four trillion, two hundred thirteen billion, five hundred twenty-two million, four hundred six thousand, seven hundred eleven".
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